f(x+3)=2x^2+5x+2

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Solution for f(x+3)=2x^2+5x+2 equation:


Simplifying
f(x + 3) = 2x2 + 5x + 2

Reorder the terms:
f(3 + x) = 2x2 + 5x + 2
(3 * f + x * f) = 2x2 + 5x + 2
(3f + fx) = 2x2 + 5x + 2

Reorder the terms:
3f + fx = 2 + 5x + 2x2

Solving
3f + fx = 2 + 5x + 2x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
-2 + 3f + fx + -5x + -2x2 = 2 + 5x + 2x2 + -2 + -5x + -2x2

Reorder the terms:
-2 + 3f + fx + -5x + -2x2 = 2 + -2 + 5x + -5x + 2x2 + -2x2

Combine like terms: 2 + -2 = 0
-2 + 3f + fx + -5x + -2x2 = 0 + 5x + -5x + 2x2 + -2x2
-2 + 3f + fx + -5x + -2x2 = 5x + -5x + 2x2 + -2x2

Combine like terms: 5x + -5x = 0
-2 + 3f + fx + -5x + -2x2 = 0 + 2x2 + -2x2
-2 + 3f + fx + -5x + -2x2 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-2 + 3f + fx + -5x + -2x2 = 0

The solution to this equation could not be determined.

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